All this work with the Fibonacci sequence and the golden ratio inspired me to go online and do a little research into other interesting mathematical relationships. In doing so I came across Pascal’s Triangle, which is well know to most, or at least most in this course have an idea of what Pascal’s Triangle is.
One interesting property of this triangle I actually came across last year while working on some other math stuff. The property is that the first 5 rows of the triangle can be constructed by considering each digit obtained by the first 5 powers of 11 (including 11^0). I only mention this because in my research I discovered that in fact this relation holds for all powers of 11. Considering the construction of each row of the triangle by way of the coefficients of the x-values of the binomial expansion of (x+y)^n (binomial theorem), which is another interesting property of the triangle, if the value of x in (x+y)^n is replaced with 10 and y is given a value of 1 for simplicity, the nonzero digits of each number in the binomial expansion (summation) are in fact the numbers for the corresponding row of the triangle. Because this can be done for all values of n in 11^n, I feel as though there must be an algorithm for constructing any given row of the triangle with no knowledge other than the value of 11^n and this particular algorithm. Although in the couple of hours I attempted to discover this algorithm, I was not able to find anything solid from which I could attempt a proof by induction. However I think this will be an interesting problem to work on.
Another interesting relation is that of Pascal’s Triangle and the Fibonacci sequence. If you consider the triangle below and only those numbers in the square parentheses, that follow a diagonal pattern, the sum of those numbers, from top left to bottom right, correspond to the Fibonacci number, F(n), where n is the row number of the last digit added along the diagonal.
1 row 1
1 1 row 2
1 2 1 row 3
[1] 3 3 1 row 4
[1] 4 [6] 4 1 row 5
1 5 [10] 10 [5] 1 row 6
1 6 15 20 [15] 6 [1] row 7, F(7) = 13 = 1 + 6 + 5 + 1
1 7 21 35 35 21 [7] 1 row 8
1 8 28 56 70 56 28 8 [1] row 9, F(9) = 34 = 1 + 10 + 15 + 7 + 1
One interesting property of this triangle I actually came across last year while working on some other math stuff. The property is that the first 5 rows of the triangle can be constructed by considering each digit obtained by the first 5 powers of 11 (including 11^0). I only mention this because in my research I discovered that in fact this relation holds for all powers of 11. Considering the construction of each row of the triangle by way of the coefficients of the x-values of the binomial expansion of (x+y)^n (binomial theorem), which is another interesting property of the triangle, if the value of x in (x+y)^n is replaced with 10 and y is given a value of 1 for simplicity, the nonzero digits of each number in the binomial expansion (summation) are in fact the numbers for the corresponding row of the triangle. Because this can be done for all values of n in 11^n, I feel as though there must be an algorithm for constructing any given row of the triangle with no knowledge other than the value of 11^n and this particular algorithm. Although in the couple of hours I attempted to discover this algorithm, I was not able to find anything solid from which I could attempt a proof by induction. However I think this will be an interesting problem to work on.
Another interesting relation is that of Pascal’s Triangle and the Fibonacci sequence. If you consider the triangle below and only those numbers in the square parentheses, that follow a diagonal pattern, the sum of those numbers, from top left to bottom right, correspond to the Fibonacci number, F(n), where n is the row number of the last digit added along the diagonal.
1 row 1
1 1 row 2
1 2 1 row 3
[1] 3 3 1 row 4
[1] 4 [6] 4 1 row 5
1 5 [10] 10 [5] 1 row 6
1 6 15 20 [15] 6 [1] row 7, F(7) = 13 = 1 + 6 + 5 + 1
1 7 21 35 35 21 [7] 1 row 8
1 8 28 56 70 56 28 8 [1] row 9, F(9) = 34 = 1 + 10 + 15 + 7 + 1
The majority of this information was obtained form Wikipedia, which is not necessarily a valid source for research but these properties are easily verified. In addition I have provided a link to the page I read, because it provides very interesting resemblance between the fractal Sierpinski’s Triangle and shading various different number patterns within Pascal’s triangle. It seems that by shading the odd numbers found with Pascal’s triangle it begins to appear as the Sierpinski Triangle.
http://en.wikipedia.org/wiki/Pascal_triangle#Other_patterns_and_properties
http://mathforum.org/workshops/usi/pascal/pascal_sierpinski.html
More to come on these relations in the future, but for now it’s a gorgeous sunny Thanksgiving Monday so I’m going to go out side and enjoy the nice weather.